My Ajax
$("form").on("submit", function () {
var data = {
"action": "test"
};
data = $(this).serialize() + "&" + $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "ajax2.php", //Relative or absolute path to response.php file
data: data,
success: function (data) {
$("#main_content").slideUp("normal",function(){
$(".the-return").html("<br />JSON: " + data);
//how to alter this part to display data for each record in one div?
});
}
});
return false;
});
My query
$statement = $pdo->prepare("SELECT * FROM posts WHERE subid IN (:key2) AND Poscode=:postcode2");
$statement->execute(array(':key2' => $key2,':postcode2'=>$postcode));
// $row = $statement->fetchAll(PDO::FETCH_ASSOC);
$json = array();
while( $row = $statement->fetch()) {
array_push($json, array($row['Name'], $row['PostUUID']));
}
header('Content-Type: application/json');
echo json_encode($json);
The result displayed currently in this form:
JSON: jack,55421894ab602,test,55439324cc43d
But I want to display like:
Name:jack,
Id:55421894ab602
.....and some other info-
Name:test
Id:55439324cc43d
.....and some other info-
This part:
$(".the-return").html("<br />JSON: " + data);
I tried: data[0];
But when I do this, only the first record displayed obviously.
What I'm trying is :
data[0]
itself is an array. How to display that array together with other records fetched in nice html?
edited: WIth these edited code, i can only retrieve the last result, it's not looping through the array.
ajax success: function (data) {
$("#main_content").slideUp("normal",function(){
//$(".the-return").html("<br />JSON: " + j_data);
for (i = 0; i < data.length; i++) {
$(".the-return").html("<div>Name:" + data[i].name + "<br/>Id:" + data[i].id);
}
console.log(data); // this shows nothing in console,I wonder why?
//alert(j_data);
});
}
php
$json = array();
while( $row = $statement->fetch()) {
//array_push($json, array($row['Name'], $row['PostUUID']));
array_push($json, array("name" => $row['Name'], "id" => $row['PostUUID']));
}
header('Content-Type: application/json');
echo json_encode($json);
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